Introduction
Understanding how to find the sum of coefficients in polynomial expansions is a fundamental skill in algebra and polynomial theory. This article will guide you through the process using the polynomial x2yZ10. We will break down the methodology and provide detailed explanations to ensure a thorough understanding.
Step-by-Step Guide to Finding the Sum of Coefficients
The sum of coefficients in a polynomial expression can be found by substituting the variables with 1. This method simplifies the expression to a straightforward calculation. Let's apply this approach to the polynomial x2yZ10.
Substitution Method and Calculation
To find the sum of coefficients in the expansion of x2yZ10, we need to substitute x 1, y 1, and Z 1 into the expression. This simplifies the polynomial to:
[(1 cdot 2 cdot 1)^{10} 2^{10}]Next, we calculate the value of (2^{10}): [2^{10} 1024]
However, we need to consider the coefficients carefully. The correct substitution should be as follows:
[(1 cdot 2 cdot 1)^{10} 4^{10}]Now, let's calculate (4^{10}): [4^{10} 2^{20} 1048576]
Generalizing the Method
The method works for any polynomial of the form (a_1x_1a_2x_2a_3x_3 cdots a_nx_n^m). By substituting (x_1 x_2 cdots x_n 1), we can simplify the expression to find the sum of the coefficients. For example, in the polynomial (ab^2), substituting (a 1) and (b 1), we get: [(1 cdot 1^2) 1]
The given polynomial (x2yZ^{10}) can be similarly simplified by substituting 1 for each variable:
[(1 cdot 2 cdot 1)^{10} (2 cdot 1)^{10} 2^{10} 4^{10}]Important Points to Remember
Always substitute each variable with 1 to find the sum of coefficients in a polynomial. The substitution method works for any polynomial, regardless of its complexity. Calculate the simplified expression carefully to ensure accuracy.Conclusion
In conclusion, to find the sum of coefficients in the expansion of x2yZ10, we followed a systematic approach by substituting x 1, y 1, and Z 1, which simplified the expression to 4^{10}. The final sum of the coefficients is 1048576. Understanding this method will help in solving similar problems efficiently.